Acid-base equilibria
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I was just wondering what the titration curve would look like if 10 cm3 of sulphuric acid were titrated with ammonia solution. 20 cm3 of ammonia is sufficient to neutralise the fully ionised sulphuric acid. Does the curve have two equivalence points? If so, where are they and why?
Igloo writes
We have no practical experience of this particular titration, so we would welcome comments from anyone who has tried this in practice.
I am assuming that the sulphuric acid and ammonia have the same concentration. If so, you are correct: 20 cm3 of ammonia will be needed to neutralize fully the sulphuric acid.
Sulphuric acid is a strong acid and ionises pretty well fully to H+ and HSO4– in aqueous solution.
The hydrogensulphate ion is a weak acid and is hardly ionised just in the presence of water.
So from an ionic point of view, the titration will take place in two stages:
[1] NH3 + H+ + HSO4– -> NH4+ + HSO4–
[2] NH3 + HSO4– -> NH4+ + SO42–
At the start of the titration we are dealing with dilute sulphuric acid, so the pH would be very low (say 1 if it is a 0.1 M solution).
This starts as a titration of a strong acid with a weak base. This should have quite a sharp end point with a pH below 7 at the equivalence point.
Whilst sulphuric acid can form acid salts with alkali metals (e.g. NaHSO4), we know of no evidence that it is possible to isolate a compound NH4HSO4), because we have never encountered this compound.
The second stage is the neutralisation of a weak acid by a weak base. This will not have a sharp end point. The end point should be detected with a titre which is twice that of the first end point.
However - we are not completely convinced by this answer so please try it and let us know.
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updated: 10 December 2003
