Carboxylic acids and related compounds
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What is the equation when ethanedioic acid is neutralised by sodium hydroxide? How is it balanced?
There are two carboxylic acid groups in ethanedioic acid (COOH)2. So 1 mol of the acid reacts with 2 mol NaOH (assuming that you add enough alkali to neutralise all the acid).
The organic product is (COONa)2.
Risk assessment
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updated: 31 January 2006
