Redox and redox equilibria
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I’m doing an experiment on the analysis of iron tablets. I haven’t done titration experiments before so I’m lost. I need to know why the iron tablets should not be heated more than necessary when dissolving in sulphuric acid, and why they are being dissolved in sulphuric acid and not water.
Igloo writes
The titration you are going to carry out almost certainly involves the redox reaction using potassium manganate(VII), and this technique relies on the fact that the iron is present in the form of Fe2+ ions. These will be oxidised to Fe3+ ions during the titration itself.
The tablets contain iron(II) sulphate, so when they are crushed and dissolved in water, iron(II) ions are released into solution. So far, so good.
Unfortunately, these ions are slowly removed in solutions with a relatively high pH (>7) for two reasons:
Firstly, they are hydrolysed by water molecules, forming insoluble iron(II) hydroxide:
Fe2+ (aq) + 2H2O(l) <=> Fe(OH)2 (s) + 2H+(aq)
Addition of acid (H+) will cause the equilibrium to adjust to the left, re-forming the Fe2+(aq) ions.
Secondly, Fe2+(aq) ions are rapidly oxidised (by the air) to Fe3+(aq) ions under alkaline conditions, and these hydrolyse even more easily to give a 'rusty' cloudiness (Fe(OH)3) to the solution. The use of sulphuric acid ensures that this process is prevented, so that your solution contains the original number of Fe2+(aq) ions from the tablet, prior to the titration with potassium manganate(VII).
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Risk assessment
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updated: 14 December 2006
